Use the coordinates of the labeled point to find the point-slope equation ofthe line.-5(3,-5)O Ay+5 = -3(x − 3)B. y + 5 =3(x+3)OC. y-3-(x+5)D. y-5=-3(x+3)9-5

Use the coordinates of the labeled point to find the pointslope equation ofthe line535O Ay5 3x 3B y 5 3x3OC y3x5D y53x395 class=

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Explanation

Given the points unlabeled point (0,4) and labeled point (3,-5) we can find the slope of the equation

The equation of a line can be gotten using the formula below.

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-5-4}{3-0}=-\frac{9}{3}=-3[/tex]

Since, (3,-5) is the only labeled point we can have the point-slope equation as;

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-5)=-3\left(x-3\right) \\ y+5=-3\left(x-3\right) \end{gathered}[/tex]

Answer: Option A

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