Question

What are the roots of f(x) = x^3+6x^2+11x+6.

Answer 1

Given the function:

$f(x)=x^3+6x^2+11x+6$

The roots of the function are the value of x which make the function f(x) = 0

We can find the roots by drawing the function

The intersection between the function and the x-axis will give the roots of the function

The graph of the function is as shown in the following picture:

As shown, the points of intersection with the x-axis are:

( -3, 0 ) and ( -2, 0) and ( -1, 0 )

so, the roots of the function are:

x = { -3, -2, -1 }