Question

a manufacturer of aspirin claims that the proportion of headache sufferers who get relief with just two aspirins is 62.9%. what is the probability that in a random sample of 400 headache sufferers, less than 58.1% obtain relief?

Answer 1

P = 0.0234

Mean = p = 0.629

StandardDeviation = \sqrt{\frac{p*(1-p))}{n}}

StandardDeviation = \sqrt{\frac{0.629*(1-0.629))}{400}}

Standard deviation = 0.0241536 = NORM.DIST(X , mean, standard deviation, 1) = NORM.DIST(0.581, 0.629, 0.0241536 , 1). P = 0.0234

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