Respuesta :

ANSWER:

[tex]\begin{gathered} y=0\rightarrow\frac{1}{3} \\ y=2\rightarrow1 \\ y=-1\rightarrow\frac{5}{8} \end{gathered}[/tex]

STEP-BY-STEP EXPLANATION:

We have the following expression:

[tex]\frac{4y-1}{5y-3}[/tex]

We evaluate in each case:

[tex]\begin{gathered} y=0 \\ \frac{4\cdot\left(0\right)-1}{5\cdot\left(0\right)-3}=\frac{0-1}{0-3}=\frac{1}{3} \\ \\ y=2 \\ \frac{4\cdot\left(2\right)-1}{5\cdot\left(2\right)-3}=\frac{8-1}{10-3}=\frac{7}{7}=1 \\ \\ y=-1 \\ \:\frac{4\cdot\left(-1\right)-1}{5\cdot\left(-1\right)-3}=\:\frac{-4-1}{-5-3}=\frac{-5}{-8}=\frac{5}{8} \end{gathered}[/tex]

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