The number of math problems phaedra has completed varies directly with the amount of time she has been working on homework.
[tex]\begin{gathered} \text{ Number of Math Problem }\propto\text{ Amount of time} \\ \text{Number of Math Problem =k(Amount of time),} \\ \text{where, k is the proportianlity constant} \end{gathered}[/tex]She completed 8 in the first 6 minutes.
8 questions are done in 5 minutes
thue the proportion ratio is express as
Number of maths problem = k(amount of time)
8 = k(6)
8 = 6k
Divide both side by 6 :
k = 8/6
Now, for 27 minutes, let number of questions are y :
Number of maths problem = k(amount of time)
y = k(27)
substitute the value of k = 8/6
[tex]\begin{gathered} y=27k \\ y=27\times\frac{8}{6} \\ y=27\times\frac{4}{3} \\ y=9\times4 \\ y=36 \\ \text{Number of questions = 36} \end{gathered}[/tex]Number of questions done in 27 minutes are 36
Answer : D) 36
