Question

I need to know if A and B are correct and I need HELP WITH C

Answer 1

SOLUTION:

Step 1:

In this question, we are given the following;

Step 2:

For Part A:

We have that:

$68^0+53^0+x=180^0(\text{ Sum of angles }ofatriangle=180^0)$$\begin{gathered} 121^0+x=180^0 \\ \text{collecting like terms, we have that:} \\ x=180^0-121^0 \\ x=59^0 \end{gathered}$

For Part B:

We have that:

$\begin{gathered} 46^0+71^0+x=180^0 \\ (\text{Sum of angles of a triangle)} \\ 117^0+x=180^0 \\ \text{collecting like terms, we have that:} \\ \text{ x = 180}^0-117^0 \\ x=63^0 \end{gathered}$

For Part C:

We have that:

$\begin{gathered} 24^0+x+x=180^0 \\ 24^0+2x=180^0 \\ collect\text{ like terms, we have that:} \\ 2x=180^0-24^0 \\ 2x=156^0 \\ \text{Divide both sides by 2, we have that:} \\ \text{x =}\frac{156^0}{2} \\ \text{x = 78}^0 \end{gathered}$