Respuesta :

Answer:

5/48

Explanation:

One object has faces numbered from 1 to 8.

• The sample space of numbers greater than 3 = {4,5,6,7,8}.

Thus:

[tex]P(\text{ rolling a number greater than 3\rparen}=\frac{5}{8}[/tex]

The other object has 6 faces labeled M, N, O, P, Q, and R.

[tex]P(\text{ rolling the letter R\rparen}=\frac{1}{6}[/tex]

Thus, the probability of rolling a number greater than 3 and the number R:

[tex]\begin{gathered} P(number\text{ greater than }4\text{ and R\rparen}=\frac{5}{8}\times\frac{1}{6} \\ =\frac{5}{48} \end{gathered}[/tex]

The answer is 5/48.

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