Given:
The given function is:
[tex]f(x)=3\sqrt[]{x+3}-6[/tex]
The zero of a function is defined as the point where the function returns value zero.
Thus,zero of the function f is values of x where f is zero.
Hence,
[tex]\begin{gathered} \Rightarrow f(x)=0 \\ \Rightarrow3\sqrt[]{x+3}-6=0 \\ \Rightarrow3\sqrt[]{x+3}=6 \\ \Rightarrow\sqrt[]{x+3}=\frac{6}{3} \\ =\sqrt[]{x+3}=2 \end{gathered}[/tex]
Squaring both sides,
[tex]\begin{gathered} x+3=2^2 \\ x+3=4 \\ x=4-3 \\ x=1 \end{gathered}[/tex]
Hence, option A) x = 1 is correct.
