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SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given points on the graph

[tex]\begin{gathered} \text{ Points are given in the form of }(x,y) \\ \therefore\text{ points are:} \\ (x_1,y_1)=(2,0) \\ (x_2,y_2)=(0,-2) \end{gathered}[/tex]

STEP 2: Write the slope-intercept form of the equation of a line

[tex]\begin{gathered} y=mx+b \\ \text{where m is the slope and b is the y-intercept} \end{gathered}[/tex]

STEP 3: Write the formula to get the equation of a line using two given points

[tex](y-y_1)=m(x-x_1)[/tex]

STEP 4: We use the given points to get the slope

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

STEP 5: Substitute the given points into the formula in step 4 to get the slope

[tex]m=\frac{-2-0}{0-2}=\frac{-2}{-2}=1[/tex]

STEP 6: Since we have a slope and two points, we use the formula in step 3 to get the function that represents the line

[tex]\begin{gathered} (y-y_1)=m(x-x_1) \\ U\sin g\text{ point }(2,0) \\ (y-0)=1(x-2) \\ y=1(x-2) \\ y=x-2 \end{gathered}[/tex]

STEP 7: We get the rational function of the line using the given hole

[tex]\begin{gathered} \text{hole}=(5,3) \\ \text{equation of line }\Rightarrow y=x-2 \\ \\ To\text{ get the rational function, we write the function of each coordinate that makes it undefined} \\ (5,3)\Rightarrow x=5\Rightarrow x-5 \\ (5,3)\Rightarrow y=3\Rightarrow y-3 \\ We\text{ divide the equation of the line in step 6 by the expressions above} \\ \text{Hence, the rational function is given as:} \\ \frac{y}{y-3}=\frac{x-2}{x-5} \end{gathered}[/tex]

Hence, the rational function representing the line with the given hole is:

[tex]\frac{y}{y-3}=\frac{x-2}{x-5}[/tex]

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