Question

Hello! Need a little help on this question, thank you!

Answer 1

Solution

Given

$\begin{gathered} f(x)=\log_2(x)+2 \\ \\ g(x)=\log_2(x^3)-6 \\ \\ h(x)=\log_2(x)+2+\log_2(x^3)-6=\log_2(x\times x^3)-4=\log_2(x^4)-4 \\ \\ =4\log_2(x)-4=4(\log_2(x)-\log_2(2))=4(\log_2(\frac{x}{2})) \\ \\ or\text{ }4\log_2(x)-4 \end{gathered}$