From the present question we have the following function:
[tex]P(t)=36,800\times2^{\frac{t}{25}}[/tex]
In 2020, we know that it has passed 10 years since 2010. For this reason, it will only take us to substitute t = 10 and perform the needed calculation, as follows:
[tex]\begin{gathered} P(t)=36,800\times2^{\frac{10}{25}}=36,800\times2^{0.4}\cong36,800\times1.31950791 \\ P(t)\cong48,557.89 \end{gathered}[/tex]
From the solution presented, we are able to conclude that the answer is the
population of:
[tex]48,558[/tex]