2.06L
According to charle's law, the volume of a given mass of gas is directly proportional to its temperature provided that the temperature is constant. Mathematically;
[tex]\begin{gathered} V\alpha T \\ V=kT \\ k=\frac{V_1}{T_1}=\frac{V_2}{T_2} \end{gathered}[/tex]Given the following parameters
Initial volume V1 = 2.0L
Initial temperature T1 = 2.0°C = 2 + 273 = 275K
Final temperature T2 = 10 + 273 = 283K
Required
New/Final volume of the gas V2
Substitute
[tex]\begin{gathered} V_2=\frac{V_1T_2}{T_1} \\ V_2=\frac{2\times283}{275} \\ V_2=\frac{566}{275} \\ V_2=2.06L \end{gathered}[/tex]Hence the new volume of the gas is 2.06L