From the question,
We are to factorize
[tex]33x^2+2x-3[/tex]This is done as follows
[tex]\begin{gathered} 33x^2+2x-3 \\ =33x^2+11x-9x-3 \end{gathered}[/tex]This is further factorized as
[tex]\begin{gathered} 33x^2+11x-9x-3 \\ =11x(3x+1)-3(3x+1) \\ =(3x+1)(11x-3) \end{gathered}[/tex]Therefore, we have
[tex]\begin{gathered} 33x^2+2x-3 \\ =(3x+1)(11x-3) \end{gathered}[/tex]