Question

Which two values of x are roots of the polynomial below?
3x2-3x+1

Answer 1

$3x^2-3x+1$

The quadratic expression above cannot be factorised.

Hence, we will use the quadratic formula to solve it.

The quadratic formua is given by the equation:

$X=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

From the given expression;

$a=3,b=-3,c=1$

Thus,

$\begin{gathered} X=\frac{-(-3)\pm\sqrt[]{(-3)^2-4(3)(1)}}{2(3)} \\ X=\frac{3\pm\sqrt[]{9-12}}{6} \end{gathered}$$\begin{gathered} X=\frac{3\pm\sqrt[]{-3}}{6} \\ X=\frac{3+\sqrt[]{-3}}{6}\text{ OR }\frac{3-\sqrt[]{3}}{6} \end{gathered}$

Hence, the correct options are Options A and E