Respuesta :

x² + 6x + 5 = 0

To find the solution, we can use the quadratic formula.

[tex]\begin{gathered} x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4(1)(5)}}{2(1)} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36^{}-20}}{2} \\ x_{1,2}=\frac{-6\pm4}{2} \\ x_1=\frac{-6+4}{2}=-1 \\ x_2=\frac{-6-4}{2}=-5 \end{gathered}[/tex]

The solutions are (-1, 0) and (-5, 0)

RELAXING NOICE
Relax

Otras preguntas