The rate at which the revenue grows is given as :
[tex]R^{^{\prime}}(t)=9.05e^{0.025t}[/tex]To obtain the retailer's revenue as a function of time, we integrate the given equation with respect to time (t)
[tex]\begin{gathered} \int R^{\prime}(t)\text{ dt = }\int 9.05e^{0.025t}\text{ dt} \\ R(t)\text{ = }\frac{9.05}{0.025}e^{0.025t}+R_0 \\ \text{Given that R}_0\text{ = 134} \\ R(t)=362e^{0.025t}\text{ + 134} \end{gathered}[/tex]The correct option is option A
