Question

The volume of the bowling ball , to the nearest tenth, is?The diameter is 8.6 inches

Answer 1

$\text{Volume}=333\text{ cubic inches}$

Explanation

we need to asume the bowling ball is a perfect sphere ( with no holes), and we can use the formula for the volume of a sphere

$\text{Volume}=\frac{4}{3}\pi\cdot radius^3$

Step 1

Let

diameter=8.6 inches

diameter= 2*radius

hence

radius=8.6 inches /2

radius=4.3 inches

Now, replace

$\begin{gathered} \text{Volume}=\frac{4}{3}\pi\cdot radius^3 \\ \text{Volume}=\frac{4}{3}\pi\cdot(4.3inches)^3 \\ \text{Volume}=\frac{4}{3}\pi\cdot79.507in^3 \\ \text{Volume}=333.038\text{ cubic inches} \\ \text{rounded} \\ \text{Volume}=333\text{ cubic inches} \end{gathered}$

I hope this helps you