Question

if x=x2+6x-40 what are the values of x?

Answer 1

The given equation is:

$x^2+6x=40$

Firstly, we are going to transfer +40 to the left hand side of the equation and this becomes:

$x^2+6x-40=0$

Secondly, we can use the method of factorization to solve the equation above, by finding the factors of 40, such that when multiplied gives -40 and when added gives +6.

The required factors for this are +10 and -4.

Thus, we have:

$\begin{gathered} x^2+10x-4x-40=0 \\ By\text{ grouping, we have:} \\ (x^2+10x)-(4x-40)=0 \end{gathered}$

This becomes:

$undefined$