If y is directly proportional to the square root of x and y = -67 when x = 9, find y if x = 81. (Round off your answer to the nearesthundredth.)

Given
y is directly proportional to square root of x.
And, y=-67, when x=9.
To find: y, if x=81.
Explanation:
It is given that,
y is proportional to square root of x.
That implies,
[tex]\begin{gathered} y\propto\sqrt{x} \\ \Rightarrow y=k\sqrt{x} \end{gathered}[/tex]Then, for x=9 and y=-67,
[tex]\begin{gathered} -67=k(\sqrt{9}) \\ -67=k(3) \\ k=-\frac{67}{3} \end{gathered}[/tex]That is,
[tex]y=-\frac{67}{3}\sqrt{x}[/tex]Then, for x=81,
[tex]\begin{gathered} y=-\frac{67}{3}(\sqrt{81}) \\ =-\frac{67}{3}(9) \\ =-67\times3 \\ =-201 \end{gathered}[/tex]Hence, the value of y is -201.