1) In this question, a good knowledge of multiplication by 12 is enough to dismiss this equation and solve it in a pretty straightforward way.
2) Which number times 12 is not the one to the right of the equation?
We can tell by looking at them that:
[tex]\begin{gathered} 6x=84 \\ 6(12)=84 \\ 72=84\text{ FALSE} \\ \\ 6x=84 \\ \frac{6x}{6}=\frac{84}{6} \\ x=14 \end{gathered}[/tex]Thus, the equation in which x=12 is not the solution is:
[tex]6x=84[/tex]