How do you do circuit 7 of Q2, the current in each arm of the circuit?

ANSWER:
55Ω
I = 0.22 amp
STEP-BY-STEP EXPLANATION:
We are divided into two parts, the first is to solve the parallel system, like this:
[tex]\begin{gathered} \frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2} \\ \text{ replacing:} \\ \frac{1}{R_T}=\frac{1}{10}+\frac{1}{10} \\ R_T=\frac{100}{10+10}=\frac{100}{20}=5\Omega \end{gathered}[/tex]Then we have a series system, therefore, we solve like this:
[tex]R_T=5+50=55\Omega[/tex]The first thing is to calculate the current, knowing that the voltage is equal to 12V, like this:
[tex]\begin{gathered} I=\frac{V}{R}=\frac{12}{55} \\ I=0.22\text{ amp} \end{gathered}[/tex]