We are given the expression below:
[tex]\lbrack44+(4\times7)\rbrack\div9-5[/tex]
To find the solution to the expression, we would make use of PEDMAS to other our steps on finding the solution. PEDMAS implies
[tex]\begin{gathered} P-Parenthesis \\ E-Exponential \\ D-Division \\ M-Multiplication \\ A-Addition \\ S-Subtraction \\ \end{gathered}[/tex]
The order of PEDMAS would then be utilized in finding the value in the question.
[tex]\begin{gathered} \lbrack44+(4\times7)\rbrack\div9-5 \\ =\lbrack44+28\rbrack\div9-5 \\ =72\div9-5 \\ =8-5 \\ =3 \end{gathered}[/tex]
Therefore, the answer is
[tex]3[/tex]
The right option is option C
