Respuesta :

The area of a sector of a circle is:

[tex]A=\pi r^2\cdot\frac{\theta}{360}[/tex]

Where θ is the angle of the arc and r is the radius.

In this case,

• r = 6mi

,

• θ = 126º

Then:

[tex]A=\pi(6mi)^2\cdot\frac{126}{360}=\pi\cdot\frac{36mi^2\cdot126}{360}=\frac{63}{5}\pi[/tex]

Thus the correct option is the 4th one:

[tex]\frac{63}{5}\pi\text{ }mi^2[/tex]

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