The figure is made up of a cone and a cylinder. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box.
![The figure is made up of a cone and a cylinder To the nearest whole number what is the approximate volume of this figure Use 314 to approximate π Enter your ans class=](https://us-static.z-dn.net/files/d4d/e9c404810eabfdb749a2ade761ca2a30.png)
38 m³
To solve this we are going to find the volumes of the cylinder and the cone separately, and then we are going to add them.
Volume of the cylinder:
[tex]V=\pi r^2h[/tex]
where
[tex]V[/tex] is the volume of the cylinder
[tex]r[/tex] is the radius
[tex]h[/tex] is the height
We can infer from the picture that the radius of the cylinder is 3 mm and its height is 2 mm, so let's replace the values
[tex]V=(3.14) (2mm)^2(2mm)[/tex]
[tex]V=(3.14)(4mm^2)(2mm)[/tex]
[tex]V=25.12mm^3[/tex]
Volume of the cone:
[tex]V=\pi r^2\frac{h}{3}[/tex]
where
[tex]V[/tex] is the volume of the cone
[tex]r[/tex] is the radius
[tex]h[/tex] is the height
We can infer from our picture that the radius of the cone is 4 mm and its height is 3 mm, so let's replace the values
[tex]V=(3.14)(2mm)^2(\frac{3mm}{3} )[/tex]
[tex]V=(3.14)(4mm^2)(1m)[/tex]
[tex]V=12.56mm^3[/tex]
Volume of the figure = area of the cylinder + area of the cone
Volume of the figure = [tex]25.12mm^3+12.56mm^3=37.68m^3[/tex]
rounded to nearest integer:
Volume of the figure = [tex]38m^3[/tex]
To, the nearest whole number the approximate volume of this figure will be 63 cubic millimeters.
Given,
The radius of the base of cylinder and cone is 2 mm.
The height of the cylinder is 4 mm.
The height of cone is 3 mm.
We have to find the volume of the figure.
Since the figure is combined of two shapes, a cone and a cylinder.
So we find the volume of each shape separately and add up to find the volume of the whole shape.
We know that volume of cylinder is,
[tex]V=\pi r^{2} \times h[/tex]
[tex]V=3.14\times 2^2\times 4[/tex]
[tex]V=3.14\times 16[/tex]
[tex]V=50.24 \ mm^3[/tex]
Now the volume of cone is,
[tex]V'=\dfrac{1}{3} \pi r^{2} \times h[/tex]
[tex]V'=\dfrac{1}{3} \times 3.14\times 2^2\times 3[/tex]
[tex]V'= 4 \times 3.14[/tex][tex]V'=12.56\ mm^3[/tex]
The volume of the figure will be
[tex]V+V'=50.24+12.56 \\V+V'=62.80\ mm^3[/tex]
So, the nearest whole number value to this volume is 63 cubic millimeters.
For more details about volume, follow the link:
https://brainly.com/question/4725130