Question

120 volts is run through a primary coil containing 200 turns. If the secondary coil has 610 turns, what will the new output voltage be?

Answer 1

We are asked to determine the output voltage of a coil with 610 turns given the number of turns and the voltage of the primary coil. To do that we will use the following formula:

$\frac{V_2}{V_1}=\frac{n_2}{n_1}$

Where:

$\begin{gathered} n_1,n_2=\text{ number of turns of the primary and secondary coil} \\ V_1,V_2=\text{ voltage of the primary and secondary coil. } \end{gathered}$

Now, we solve for V2 by multiplying both sides by V1:

$V_2=\frac{n_2}{n_1}V_1$

Now, we substitute the values:

$V_2=\frac{610}{200}(120V)$

Solving the operations:

$V_2=366V$

Therefore, the voltage of the secondary coil is 366V.