Respuesta :

[tex]\angle X+106^0+31^0=180^0(\text{Sum of angles in a triangle)}[/tex][tex]\begin{gathered} \angle X+137^0+180^0 \\ \angle X=180^0-137^0 \\ \angle X=43^0 \end{gathered}[/tex]

From Triangle 1,

∠X=43°

[tex]\begin{gathered} \angle Y+31^0+43^0=180^0 \\ \angle Y+74^0=180^0 \\ \angle Y=180^0-74^0 \\ \angle Y=106^0 \end{gathered}[/tex]

From Triangle 2,

∠y=106°

Hence,

Are the figures similar? YES

∠X=43°

∠Y=106°

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