Evaluate;
[tex]\begin{gathered} f(x)=2(x^2+5)-4 \\ f(-2)=2(-2^2+5)-4 \\ f(-2)=2(4+5)-4 \\ f(-2)=2(9)-4 \\ f(-2)=18-4 \\ f(-2)=14 \end{gathered}[/tex]Kylie was not correct
At the point where she wrote down "negative 2 raised to the power of 2" (line 2 of our own solution), the result should have been 4, and not negative 4.
When a negative number is multiplied by another negative number, the answer is always positive. Hence whenever we have a negative number raised to the power of two, the answer is always a positive number.
Her next line now had "-4 + 5" instead of "4 + 5"