Question

kingsley then adds 41.84 ml of naoh to 250.00 ml of the hcooh solution. the neutralization reaction resulted in 0.086 moles of hcooh and 0.029 moles of hcoo- left in solution. determine the ph of the resulting solution.

Answer 1

According to the given statement is The pH of the resulting solution is 3.28.

What are neutralization reactions?

In a neutralization reaction, an acid and a base mix chemically to yield salt and water as the final products. In a neutralization process, water is produced when H+ and OH- ions are combined. In a neutralization reaction, which takes place when an acid and a base combine to generate water and a salt, the interaction of H+ ions and OH- ions results in the production of water. The pH of a strong acid and strong base when they are neutralized by one another is 7.

Briefing:

Final Volume = 41.84 mL + 250 mL = 291 mL

= 291 mL / 1000

= 0.291 L

[HCOO⁻] = 0.029 mol / 0.294 L = 0.098 M

[HCOOH] = 0.086 mol / 0.294 L = 0.292 M

So, the pH should be

= 3.75 + log0.098/0.292

= 3.28

The pH of the resulting solution is 3.28.

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