To add, (2xy²+ 15x – 6) + (3xy² – y + 5)
Explanation:
It is given that,
(2xy²+ 15x – 6) + (3xy² – y + 5)
That implies,
[tex]\begin{gathered} \left(2xy²+15x-6\right)+(3xy²-y+5)=(2xy^2+3xy^2)+15x-y+(-6+5) \\ =5xy^2+15x-y-1 \end{gathered}[/tex]Hence, the answer is 5xy² +15x -y-1.