We are given
Principal (P) = $2000
Rate (r) = 7% = 0.07
We want to find the amount at the end of 1 year and 2 years compound interest
Solution
Recall the formula for the compound interest
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
Here
[tex]\begin{gathered} A\text{ = amount} \\ n\text{ = }numberoftimesinterestappliedpertimeperiod \\ t\text{ = time} \end{gathered}[/tex]
other parameters have been defined earlier above
Part A
Find the amount in the account at the end of 1 year.
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ A=2000(1+\frac{0.07}{1})^{(1)(1)} \\ \text{Notice that n = 1 and t = 1 year} \\ A=2000(1+0.07)^1 \\ A=2000(1.07) \\ A=2140 \end{gathered}[/tex]
Therefore amount = $2140
Part B
Find the amount in the account at the end of 2 years.
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ A=2000(1+\frac{0.07}{1})^{(1)(2)} \\ \text{Notice that n = 1 and t = 2 years} \\ A=2000(1+0.07)^2 \\ A=2000(1.07)^2 \\ A=2000(1.1449) \\ A=2289.8 \end{gathered}[/tex]
Therefore, the amount = $2289.8