Respuesta :

Explanation

In the question, we are given that Mrs.Singh purchased 31 softcover books and hardcover books. Let softcover books and the hardcover book be x and y respectively.

Therefore;

[tex]x+y=31----1[/tex]

Also, each softcopy book costs $3.50 and hard copy books cost $14.50.

[tex]3.50x+14.50y=240.50---2[/tex]

The next step is to solve the simultaneous equation.

[tex]x=31-y------3[/tex]

Substitute equation iii into ii

[tex]\begin{gathered} 3.50(31-y)+14.50y=240.50 \\ 108.50-3.50y+14.50y=240.50 \\ 11y=240.50-108.50 \\ 11y=132 \\ \frac{11y}{11}=\frac{132}{11} \\ y=12 \end{gathered}[/tex]

Next, we substitute the value of y in equation iii

[tex]\begin{gathered} x=31-12 \\ x=19 \end{gathered}[/tex]

Therefore the answers are:

Soft cover books: 19 books

Hard coverbooks: 12 books

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