Question

Two parallel plates have an area of0.188 m². How much charge must youplace on them to create a 37000 N/Cfield between the plates?[?]. 10⁰¹ C

Answer 1

Given:

The area of the plate is: A = 0.188 m²

The field produced between the plates is: E = 37000 N/C

To find:

The charge to be placed on the plates.

Explanation:

The electric field produced between two parallel plates is given as:

$E=\frac{Q}{A\epsilon_0}$

Here, Q is the charge on the parallel plates and ε₀ is the permittivity of free space having a value of 8.85 × 10⁻¹² C²/N.m²

Rearranging the above equation, we get:

$Q=EA\epsilon_0$

Substituting the values in the above equation, we get:

$\begin{gathered} Q=37000\text{ N/C}\times0.188\text{ m}^2\times8.85\times10^{-12}\text{ C}^2\text{/N.m}^2 \\ \\ Q=6.156\times10^{-8}\text{ C} \end{gathered}$

Final answer:

The amount of charge to be placed on parallel plates is 6.156 × 10⁻⁸ C.