Question

Factor completely:x to the second power minus x minus 6?A. ( x - 2) (x + 3)B. (x - 1) (x - 6)C. (x + 2) (x - 3)D. (x + 1) ( x - 6)

Answer 1

x to the second power minus x minus 6 can be expressed below

$x^2-x-6$

Therefore, the quadratic equation can be factorise as follows

$\begin{gathered} x^2-x-6 \\ \text{ find 2 numbers you can multiply to get -6 and add to get -1. } \\ \text{The 2 numbers are }2\text{ and -3.} \\ \text{Therefore,} \\ x^2+2x-3x-6 \\ x(x+2)-3(x+2) \\ (x-3)(x+2) \end{gathered}$