Question

To find the area of a trapezoid, Dylan uses the formula A=1/2(b1+b2)h The bases have lengths of 3.6 cm and 12 1/3. The height of the trapezoid is the square root of 5. The area of the trapezoid is irrational because

Answer 1

its 75 i jus did it

Answer 2

Answer:

Step-by-step explanation:

It is given that the base lengths of the trapezoid are $36 cm$ and $12\frac{1}{3} cm$ and the height of the trapezoid is $\sqrt{5} cm$.

Now, the area of the trapezoid is given as:

$A=\frac{1}{2}(b_{1}+b_{2})h$

Substituting the given values, we get

$A=\frac{1}{2}(3.6+12\frac{1}{3})\sqrt{5}$

$A=\frac{1}{2}(3.6+\frac{37}{3})\sqrt{5}$

$A=\frac{1}{2}(3.6+12.33)\sqrt{5}$

$A=\frac{1}{2}(15.93)\sqrt{5}$

$A=7.96\sqrt{5} cm^2$

which is the required area of teh trapezoid.

The area of the trapezoid is irrational because it consists of an irrational term that is $\sqrt{5}$.