Given data
*The given weight of the cart is W = 70 N
*The given distance is s =50 m
*The given initial velocity of the cart is u = 0 m/s
*The given force exerted on the cart is F = 1400 N
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The mass of the cart is calculated as
[tex]\begin{gathered} W=mg \\ m=\frac{W}{g} \\ =\frac{70}{9.8} \\ =7.14\text{ kg} \end{gathered}[/tex]The formula for the acceleration of the car is given by the equation of motion as
[tex]\begin{gathered} F=ma \\ a=\frac{F}{m} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} a=\frac{1400}{7.14} \\ =196.0m/s^2 \end{gathered}[/tex]The formula for the final velocity of the cart is given by the equation of motion as
[tex]v^2=u^2+2as[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} v^2=(0)^2+2(196)(50) \\ v=\sqrt[]{19600} \\ =140\text{ m/s} \end{gathered}[/tex]Hence, the final velocity of the cart is v = 140 m/s
