Question

What is the perimeter of a rectangular picture frame that is 14 1/2 inches tall and 11 1/2 inches wide?

Answer 1

You have a rectangular picture with the following sides:

-t: tall = 14 1/2

-w: wide = 11 1/2

You first exprese the previous numbers as normal fractions:

$\begin{gathered} 14\text{ }\frac{1}{2}=\frac{14}{1}+\frac{1}{2}=\frac{28+1}{2}=\frac{29}{2} \\ 11\frac{1}{2}=\frac{11}{1}+\frac{1}{2}=\frac{22+1}{2}=\frac{23}{2} \end{gathered}$

Next, you use the following formula for the perimeters of a rectangle

$P=2t+2w$

By replacing the values of t and w you obtain:

$P=2(\frac{29}{2})+2(\frac{23}{2})=29+23=52$

Hence, the perimeter of the given rectangle is 52 inches