Question

5. What is the standard equation of the circle graphed?.c.+a. (x-3)²+(y-2)² = 2(x-3)+(y-1) = 4b.(x+3)* +(y +1) = 2d. (x+3)+(y +1)* = 4.

Answer 1

The general equation for a circle with radius r centered in (a,b) is given by:

$(x-a)^2+(y-b)^2=r^2$

Since the circle in the picture is centered at (3,1) and has radius r = 2, its equation is given by:

$(x-3)^2+(y-1)^2=4$

Answer: b