please fill in the blanks of the question i sent a pic of

Solution
- The diameter of a circle is the longest chord of a circle.
- Thus, the coordinate of the center of the circle is the midpoint of the diameter or longest chord.
[tex]\begin{gathered} \text{ The formula for finding the Midpoint is:} \\ M(x,y)=(\frac{x_2+x_1}{2},\frac{y_2+y_1}{2}) \\ \\ (x_1,y_1)=(4,5.5) \\ (x_2,y_2)=(4,10.5) \end{gathered}[/tex]- Thus, we can solve the question as follows:
[tex]\begin{gathered} M=\frac{4+4}{2},\frac{10.5+5.5}{2} \\ \\ M=(4,8) \end{gathered}[/tex]The center of the circle is (4, 8)
- The radius can be gotten by finding the distance between the coordinate of the center and any of the endpoints of the diameter.
- Thus, we have:
[tex]\begin{gathered} D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ r=\sqrt{(4-4)^2+(8-5.5)^2} \\ \\ r=\sqrt{2.5^2} \\ \\ r=2.5 \end{gathered}[/tex]- The radius has a magnitude of 2.5 units
- The equation of the circle can be gotten by the formula given below:
[tex]\begin{gathered} \text{ Equation of a circle} \\ r^2=(x-a)^2+(y-b)^2 \\ where, \\ (a,b)\text{ is the center of the circle} \\ r\text{ is the radius} \\ \\ 2.5^2=(x-4)^2+(y-8)^2 \end{gathered}[/tex]The equation of the circle becomes:
[tex](x-4)^2+(y-8)^2=2.5^2[/tex]