Answer:
366 feet
Explanation:
The two semicircles have a diameter of 40 feet.
[tex]\begin{gathered} \text{Radius}=\frac{40}{2} \\ =20\text{ feet} \end{gathered}[/tex]First, find the perimeter of the two semicircles:
[tex]\begin{gathered} P=2(\frac{2\pi r}{2})=2\pi r \\ =2\times\frac{22}{7}\times20 \\ =125.71\; ft \end{gathered}[/tex]Therefore, the approximate perimeter of the track is:
[tex]\begin{gathered} P=125.71+120+120 \\ =365.71 \\ \approx366\; ft \end{gathered}[/tex]The approximate perimeter of the track is 366 feet.