Question

what is the solution to 32≥2h+6h

Answer 1

Let's begin by identifying key information given to us:

$\begin{gathered} 32\ge2h+6h​ \\ 32\ge8h​ \\ \text{Divide both sides by ''8'', we have:} \\ \frac{32}{8}\ge\frac{8}{8}h​ \\ 4\ge h \\ h\le4 \end{gathered}$