Respuesta :

Given the system of equations;

[tex]\begin{gathered} 4x+2y=6\ldots\ldots\ldots\ldots\ldots\ldots..equation\text{ 1} \\ y=-2x+3\ldots\ldots\ldots\ldots\ldots\ldots.equation\text{ 2} \end{gathered}[/tex]

Then, we will check if the given pair is a solution by substituting in both equations, we have;

[tex]\begin{gathered} 4x+2y=6 \\ x=-2,y=7 \\ 4(-2)+2(7)=6 \\ -8+14=6 \\ 6=6 \end{gathered}[/tex]

Then, it is true for equation 1.

Also,

[tex]\begin{gathered} x=-2,y=7 \\ 7=-2(-2)+3 \\ 7=4+3 \\ 7=7 \end{gathered}[/tex]

Thus, it is true for equation 2.

Hence, the given pair is a solution.

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