Given:
[tex](x,\frac{3}{4})\text{ and (1,0) points lies on the circle.}[/tex]
Equation of circle is
[tex]x^2+y^2=r^2[/tex][tex]\begin{gathered} x^2+(\frac{3}{4})^2=1^2 \\ x^2+\frac{9}{16}=1 \\ x^2=1-\frac{9}{16} \\ x^2=\frac{16-9}{16} \\ x^2=\frac{7}{16} \\ x=-\frac{\sqrt[]{7}}{4} \end{gathered}[/tex]
