We have the following:
A.
[tex]\begin{gathered} 2y=-3x+16 \\ \frac{2}{2}y=-\frac{3}{2}x+\frac{16}{2} \\ y=-\frac{3}{2}x+8 \end{gathered}[/tex][tex]\begin{gathered} y=-\frac{3}{2}\cdot0+8 \\ y=8 \end{gathered}[/tex]
A solution to this equation (0, 8)
B.
[tex]\begin{gathered} y=-\frac{3}{2}\cdot28+8=-3\cdot14+8 \\ y=-42+8 \\ y=-34 \end{gathered}[/tex]
The point is (28, -34)
