Respuesta :

From the trigonometric identities, we know that

[tex]\sec \theta=\frac{1}{\cos \theta}[/tex]

From the given triangle, we can see that

[tex]\cos \theta=\frac{15}{17}[/tex]

then,

[tex]\sec \theta=\frac{1}{\frac{15}{17}}[/tex]

so, the answer is

[tex]\sec \theta=\frac{17}{15}[/tex]

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