Question

Find the area of the figure. Dimensions are in inches

Answer 1

We are given a figure and we are asked to determine its area. To do that we need to add the areas of the square and the semi-circle. The area of the square is the measure of its side squared, that is:

$A_s=l^2$

Replacing:

$\begin{gathered} A_{}s=(6in)^2 \\ A_{}s=36in^2 \end{gathered}$

The area of the semi-circle is given by:

$A_{sc}=\frac{\pi r^2}{2}$

Replacing the value of the radius:

$A_{sc}=\frac{\pi(3in)^2}{2}$

Solving the operations:

$A_{sc}=14.1in^2$

The total area is:

$A=A_s+A_{sc}$

Replacing:

$\begin{gathered} A=36in^2+14.1in^2 \\ A=50.1in^2 \end{gathered}$

Therefore, the area is 50.1 square inches.