A six-sided dice is rolled twice. Find the probability that the larger of the two rolls was less than or equal to 4. Round your answer to four decimal places.
[tex]\begin{gathered} \text{there are 4 numbers in a dice that are less or equal to 4: 1,2,3,4} \\ so\text{ we have that this probability is } \\ \frac{4}{6}\cdot\frac{4}{6}=\frac{16}{36}=\frac{4}{9}=0.4444 \end{gathered}[/tex]
