Question

Find the vertex of the function given below. у= 2х^2 + 4х+1 ОА. (1,7) ов. (-1, -1)с. (3, -4) D. (-4, 9)

Answer 1

Given the function:

$y=2x^2+4x+1$

To find the vertex, first use the formula below to find x:

$x\text{ = }\frac{-b}{2a}$

Where b = 4 and a = 2 from the equation.

we have:

$x\text{ = }\frac{-b}{2a}=\frac{-4}{2\ast2}\text{ = }\frac{-4}{4}\text{ = -1}$

Since x = -1, to find y, substitute x for -1 in the equation:

$\begin{gathered} y=2x^2+4x+1 \\ \\ \text{ = 2(-1)}^2+4(-1)+1 \\ \\ \text{ = 2 - 4 + 1 = }-1 \end{gathered}$

Therefore the vertex is: (-1, -1)

ANSWER:

(-1, -1)