Question

The formula for throwing a baseball in the air is represented by :h = -16t² + 12t + 40where h is the height of the ball and t is the time in secondsNow we need to find after how many seconds will the ball hit the groundWhen the ball hits the ground the height of the ball is 0

Answer 1

We will determine the time as follows:

$-16t^2+12t+40=0\Rightarrow t=\frac{-(12)\pm\sqrt[]{(12)^2-4(-16)(40)}}{2(-16)}$$\Rightarrow\begin{cases}t=-\frac{5}{4} \\ \\ t=2\end{cases}$

So, at t = 2 the ball will hit the ground.