Respuesta :

Given a diameter LM and its coordinates.

The coordinate of the center is the midpoint of LM

Midpoint = [(x1 + x2)/2, (y1 + y2)/2]

Coordinate of the center = [(-4+12)/2, (-8+4)/2]

Coordinate of the center = (4, -2)

Now to get the length of the radius, get the distance of LM and divide it by 2 :

[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex][tex]d=\sqrt[]{(4+8)^2+(12+4)^2}[/tex]

d = 20

and the radius is 20/2 = 10

Now we have the center at (4, -2) and a radius of 10

The standard equation of a circle is :

(x-h)^2 + (y-k)^2 = r^2

where h and k are the center of the circle (h, k)

So the equation will be :

(x-4)^2 + (y+2)^2 = 10^2

or

(x-4)^2 + (y+2)^2 = 100

RELAXING NOICE
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