The general equation of a circle is:
[tex](x-a)^2+(y-b)^2=r^2.[/tex]
Where r is the radius and (a, b) is the centre.
We have the circle Q represented by the following equation:
[tex](x-11)^2+(y+15)^2=7.[/tex]
To identify the elements of the circle, we write the last equation as:
[tex](x-11)^2+(y+15)^2=(\sqrt[]{7})^2.[/tex]
Comparing this equation we the general equation above, we see that the radius is:
[tex]r=\sqrt[]{7}.[/tex]
Segment KL is the diameter of the circle. Because the diameter is two times the radius, we have:
[tex]KL=d=2r=2\cdot\sqrt[]{7}.[/tex]
Answer
C. 2√7
